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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA milkman mixes 40 litres of water with 60 litres of milk. After selling onefourth of this mixture, he adds water to replenish the quantity that he had sold. What is the current proportion of water to milk?
Correct
EXPLANATION
Milk : Water = 60 : 40
Selling onefourth i.e 25% of mixture.
The amount of milk sold is 60% of 25 = 15 lt
The amount of water sold is 40% of 25 = 10 lt
Amount of milk left = 60 – 15 = 45 lt
Amount of water left = 40 – 10 = 30 ltr
To replenish the quantity sold he has to add 25 lt (15+10 )water
So amount of water left = 30 + 25 = 55
Ratio of milk and water = 45 : 55 = 9 : 11Incorrect
EXPLANATION
Milk : Water = 60 : 40
Selling onefourth i.e 25% of mixture.
The amount of milk sold is 60% of 25 = 15 lt
The amount of water sold is 40% of 25 = 10 lt
Amount of milk left = 60 – 15 = 45 lt
Amount of water left = 40 – 10 = 30 ltr
To replenish the quantity sold he has to add 25 lt (15+10 )water
So amount of water left = 30 + 25 = 55
Ratio of milk and water = 45 : 55 = 9 : 11 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeMr.Vinith started a business investment 25,000 in 2013. In 2014, he invested an additional amount of 10,000 and Mr. Krishna joined him with an amount of 35,000. In 2015, Mr.Vinith invested another additional amount of 10,000 and Mr.Gopal joined them with an amount of 35,000. What will be Krishna’s share in the profit of 1,50,000 earned at the end of three years from the start of the business in 2013 ?
Correct
EXPLANATION
Vinith’s equivalent capital = (25000 × 3) + (10000 × 2) + (10000 × 1) = 105000
Krishna’s equivalent capital = 35000 ×2 = 70000
Gopal’s equivalent capital = 35000 × 1 = 35000
Vinith : Krishna : Gopal = 105 : 70 : 35 = 3 : 2 : 1
Krishna’s share in the total profit = 2*150000/6 = 50000Incorrect
EXPLANATION
Vinith’s equivalent capital = (25000 × 3) + (10000 × 2) + (10000 × 1) = 105000
Krishna’s equivalent capital = 35000 ×2 = 70000
Gopal’s equivalent capital = 35000 × 1 = 35000
Vinith : Krishna : Gopal = 105 : 70 : 35 = 3 : 2 : 1
Krishna’s share in the total profit = 2*150000/6 = 50000 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeJeeva, Vikash and Gowtham start from the same place and travel in the same direction at speeds of 40, 60 and 80 km per hour respectively. Vikash starts two hours after Jeeva. If Vikash and Gowtham overtake Jeeva at the same instant, how many hours after Jeeva did Gowtham start?
Correct
EXPLANATION
Assume that Jeeva started running at 10 a.m. and Vikash started at 12 noon.
So, in these two hours distance traveled by Jeeva is 80 km and the relative speed of Vikash w.r.t Jeeva is 20 km/hr.
So Vikash will overtake Jeeva after = 80/20 = 4 hours
So, Vikash reaches there at 4 p.m.
Gowtham also overtakes Jeeva at 4 p.m.
Assume Gowtham takes ‘t’ time to overtake
The relative speed of Gowtham w.r.t Jeeva is 40 km/hr and Jeeva ran for 6 hrs.(4+2 = 6hrs )
So, distance travelled by Jeeva is = 40 × 6 = 240 km
While distance travelled by Gowtham = 80t
240 = 80t ⇒ t = 3
Hence, Gowtham start running 3 hours after Jeeva.Incorrect
EXPLANATION
Assume that Jeeva started running at 10 a.m. and Vikash started at 12 noon.
So, in these two hours distance traveled by Jeeva is 80 km and the relative speed of Vikash w.r.t Jeeva is 20 km/hr.
So Vikash will overtake Jeeva after = 80/20 = 4 hours
So, Vikash reaches there at 4 p.m.
Gowtham also overtakes Jeeva at 4 p.m.
Assume Gowtham takes ‘t’ time to overtake
The relative speed of Gowtham w.r.t Jeeva is 40 km/hr and Jeeva ran for 6 hrs.(4+2 = 6hrs )
So, distance travelled by Jeeva is = 40 × 6 = 240 km
While distance travelled by Gowtham = 80t
240 = 80t ⇒ t = 3
Hence, Gowtham start running 3 hours after Jeeva. 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeIn a library 20% books are in Science, 50% of the remaining are in Social and the remaining 9000 are in various other subjects. What is the total number of books in Social.
Correct
EXPLANATION
Let the no of books be x
Science books = 20% of x = 20/100 = x /5
Remaining = x – x /5 = 4x / 5
Social books = 50/ 100 x 4x / 5 = 2x/ 5
For other Subjects=> x – (x/5 + 2x/5) = 9000
2x / 5 = 9000
X = 22500
Social = 2*22500/5 = 9000Incorrect
EXPLANATION
Let the no of books be x
Science books = 20% of x = 20/100 = x /5
Remaining = x – x /5 = 4x / 5
Social books = 50/ 100 x 4x / 5 = 2x/ 5
For other Subjects=> x – (x/5 + 2x/5) = 9000
2x / 5 = 9000
X = 22500
Social = 2*22500/5 = 9000 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRahul and Murali buy two goods for Rs. 2000 and Rs. 3000 respectively. Rahul marks his goods up by x%, while Murali marks his goods up by 2x%. If the profit of Murali is Rs.12000 more than Rahul find x ?
Correct
EXPLANATION
SP of Rahul = 2000 + 2000*x = 2000 (1 + x)
Profit of Rahul = 2000 (1 + x) – 2000
SP of Murali = 3000 + 3000*2x = 3000 (1 + 2x)
Profit of Murali = 3000 (1 + 2x) – 3000
Diff of profit = 12000
[3000 (1 + 2x) – 3000] – [2000 (1 + x) – 2000] = 12000
4000x = 12000
X = 3Incorrect
EXPLANATION
SP of Rahul = 2000 + 2000*x = 2000 (1 + x)
Profit of Rahul = 2000 (1 + x) – 2000
SP of Murali = 3000 + 3000*2x = 3000 (1 + 2x)
Profit of Murali = 3000 (1 + 2x) – 3000
Diff of profit = 12000
[3000 (1 + 2x) – 3000] – [2000 (1 + x) – 2000] = 12000
4000x = 12000
X = 3 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA boat can travel 8.4km downstream in 14min. If the ratio of the speed of the boat in still water to the speed of the stream is 8:1. How much time will the boat take to cover 16.8km upstream?
Correct
Explanation :
Speed = 8x:x
Downstream = 9x; upstream = 7x
Downstream speed = 8.4*60/14 = 36kmph
9x = 36
X = 4
Upstream = 7*4 = 28kmph
Time taken for 16.8km = 16.8*60/28 = 36minIncorrect
Explanation :
Speed = 8x:x
Downstream = 9x; upstream = 7x
Downstream speed = 8.4*60/14 = 36kmph
9x = 36
X = 4
Upstream = 7*4 = 28kmph
Time taken for 16.8km = 16.8*60/28 = 36min 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeAn amount of money is to be distributed among three friends Prem, Arun and Jaya in the ratio 3 : 1 : 5. The difference between Arun’s and Jaya’s share is Rs. 3600. What is the total of Prem’s and Arun’s share?
Correct
EXPLANATION
Given Ratio of distribution = 3 : 1 : 5
Let the share of Prem, Arun and Jaya be 3x, x and 5x, respectively
Since, Difference between Arun’s and Jaya’s share is Rs. 3600.
5x – x = 3600
x = 900
Prem’s share = 3 × 900 = 2700
Arun’s share = 900
Hence, Total of Prem’s and Arun’s share = Rs 3600Incorrect
EXPLANATION
Given Ratio of distribution = 3 : 1 : 5
Let the share of Prem, Arun and Jaya be 3x, x and 5x, respectively
Since, Difference between Arun’s and Jaya’s share is Rs. 3600.
5x – x = 3600
x = 900
Prem’s share = 3 × 900 = 2700
Arun’s share = 900
Hence, Total of Prem’s and Arun’s share = Rs 3600 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA sum of Rs 4000 was lent partly at 5% and partly at 8% interest. Total interest received after 3 years was Rs 717. Find the ratio of the money lent at 5% and 8%.
Correct
Explanation :
Suppose money lent at 5% = Rs x
Money lent at 8% = Rs (4000 – x)
Time (T) = 3 years
Interest in the first case = x*5*3/100 = 15x/100
Interest in the second case = Rs (4000 – x)*8*3/100
According to the question,
15x/100 + (3100 – x)*8*3/100 = 717
15x + 96000 – 24x = 71700
9x = 24300
x = Rs 2700
Other amount = Rs (4000 – 2700) = Rs 1300
Hence, ratio of money lent
= 2700: 1300 = 27:13Incorrect
Explanation :
Suppose money lent at 5% = Rs x
Money lent at 8% = Rs (4000 – x)
Time (T) = 3 years
Interest in the first case = x*5*3/100 = 15x/100
Interest in the second case = Rs (4000 – x)*8*3/100
According to the question,
15x/100 + (3100 – x)*8*3/100 = 717
15x + 96000 – 24x = 71700
9x = 24300
x = Rs 2700
Other amount = Rs (4000 – 2700) = Rs 1300
Hence, ratio of money lent
= 2700: 1300 = 27:13 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIn a three digit number the digit in the unit’s place is twice the digit in the ten’s place and three times the digit in the hundred’s place. If the sum of all the three digits of the number is 11, what is the number?
Correct
Explanation :
100a + 10b + c
c = 2b –> b = c/2
c = 3a —> a = c/3
c/3 + c/2 + c = 11
c = 6, b = 3, a = 2 => 236Incorrect
Explanation :
100a + 10b + c
c = 2b –> b = c/2
c = 3a —> a = c/3
c/3 + c/2 + c = 11
c = 6, b = 3, a = 2 => 236 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA bag contains 6 Black and 7 White balls. Four balls are drawn out one by one and not replaced. What is the probability that they are alternatively of different colours?
Correct
Explanation :
Balls are picked in two manners – BWBW or WBWB
So probability = (6/13)*(7/12)*(5/11)*(6/10) + (7/13)*(6/12)*(6/11)*(5/10) = 42/286 = 21/143Incorrect
Explanation :
Balls are picked in two manners – BWBW or WBWB
So probability = (6/13)*(7/12)*(5/11)*(6/10) + (7/13)*(6/12)*(6/11)*(5/10) = 42/286 = 21/143
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